Math, asked by shrutikashetty80, 5 months ago

3 Marks :
If a and ß are the zeroes of the polynomial
6y2 – 7y + 2, find a quadratic polynomial
1
whose zeroes are
1/a
and 1/b

Answers

Answered by Anonymous
5

Answer:

Let, a and b be the zeroes of 6y^2-7y+2

here, a+b = 7/6

b = 1/3

Here, 1/a+1/b = (a+b)/ab = 7/2

1/ab = 3

Required polynomial = y^2-(7/2)y+3

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