Question

3 moles of hydrogen at NTP are allowed to expand adiabatically so that the temperature of the gas falls to 263 K find work done by the gas​

Answer 1

Answer:

Given:-

3 moles of hydrogen at NTP are allowed to expand adiabatically so that the temperature of the gas falls to 263 K find work done by the gas

To Find:-

Work done by the gas when 3 moles expands adiabatically when Gama=1.4

Solution:-

Here,

—→ Moles of hydrogen gas=3

—→Temperature=263 kelvin.

—→ Adiabatic (no heat exchange, q=o)

—→Temperature is variable.

Formula:-

• W=nR/y-1(T1-T2)
• n=3
• y=1.4
• T1=263kelvin
• T2=0
• R=8.314 joules/mol k

Substitute all the given values:-

W= nR/y-1(T2-T1)

W= 3×8.314/1.4-1 (263)

W= 24.942/0.4 (263)

W=62.355 (263)

W=16399.365 Joules.

W=16399.365 Joules= 16.4 KJ (approx).

Conclusion

This formula is derived with the help of ideal gas equation (PV=nRT).

If you want derivation of this equation the n like my answers. Hope for the best.

Additional information:-

1. when there is temperature difference the use this formula.
2. For adiabatic process there is no exchange of heat between system and surrounding
3. NTP stands for Normal temperature and pressure
4. Normal temperature= 20celsius or 293.15k
5. Normal pressure= 1 atm