Question

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Answer 1

Question :

Out of two workers X and Y , X is twice as good as Y to perform the work assigned to them. If X can finish the assigned work in 40 days less than Y, then how many days they can finish the work if there work together ?

Solution :

Let the no. of days taken to finish the work by X be x days

X is twice as good as Y to perform the work

So, No. of days taken by Y to finish the work = 2x days

Given :

X can finish the assigned work in 40 days less than Y

⇒ x = 2x - 40

⇒ 40 = 2x - x

⇒ x = 40

X can finish the work in = 40 days

X's 1 day work = 1 / 40 of work

Y can finish the work in = 2x = 2 × 40 = 80 days

Y's 1 day work = 1 / 80 of work

( X + Y )'s 1 day work = X's 1 day work + Y's 1 day work

= ( 1 / 40 ) + ( 1 / 80 )

= ( 2 + 1 ) / 80

= 3 / 80

( X + Y ) can finish the work in = 80 / 3 = 26 2/3 days

Therefore, they take 26 2/3 days to finish the work if they work together.

Answer 2

Answer:

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