3. Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:
(a) broke even, (b) lost 4 cents, (c) gained 4 cents, (d) lost 10 cents, (e) gained 10 cents
Answers
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Solution:
Income from $ 4000 at 5 % in one year = $ 4000 of 5 %.
= $ 4000 × 5/100.
= $ 4000 × 0.05.
= $ 200.
Income from $ 3500 at 4 % in one year = $ 3500 of 4 %.
= $ 3500 × 4/100.
= $ 3500 × 0.04.
= $ 140.
Total income from 4000 at 5 % and 3500 at 4 % = $ 200 + $ 140 = $ 340.
Remaining income amount in order to have a yearly income of $ 500 = $ 500 - $ 340.
= $ 160.
Total invested amount = $ 4000 + $ 3500 = $7500.
Remaining invest amount = $ 10000 - $ 7500 = $ 2500.
We know that, Interest = Principal × Rate × Time
Interest = $ 160,
Principal = $ 2500,
Rate = r [we need to find the value of r],
Time = 1 year.
160 = 2500 × r × 1.
160 = 2500r
160/2500 = 2500r/2500 [divide both sides by 2500]
0.064 = r
r = 0.064
Change it to a percent by moving the decimal to the right two places r = 6.4 %
Therefore, he invested the remaining amount $ 2500 at 6.4 % in order to get $ 500 income every year.
Answer: (e)
Answer:
Let The Cost Price for the first pipe be "x" Dollars
Selling Price = x + 20% of x
1.20 = x + 20x / 100
1.20 = x + x/5
1.20 = (5x + x)/5
1.20 * 5 = 6x
6 = 6x
x = 1 Dollar
So ,
Cost Price of The Pipe in Which Mr. Jones Got Profit of 20% = 1 Dollar
Let The Cost Price Of The Second Pipe be "y" dollar
Selling Price of second Pipe = y - 20% of y
1.20 = y - 20y/100
1.20 = y - y/5
1.20 = (5y - y)/5
1.20 * 5 =4y
6 = 4y
y = 6/4
y = 3/2
y = 1.5 Dollars
Total Cost Price Which Mr Jones Paid = 1 + 1.5
= 2.5 Dollars
Total Selling Price Which Mr Jones Received = 1.2 + 1.2
= 2.4 Dollar
Mr. Jones Lost 10 cents
so,
ANSWER = (d) = lost 10 cents
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