Social Sciences, asked by ranjanshetty2109, 4 months ago

3. Name the Wodeyar King who contributed to the
development of Mysuru Kingdom during early part of
20th century.​

Answers

Answered by Anonymous
1

Explanation:

By using the formula,

A = P (1 + R/100) n

Let us solve

(i) Given, P = Rs 3000, rate = 5%, time = 2years

A = P (1 + R/100) n

= 3000 (1 + 5/100)2

= 3000 (105/100)2

= Rs 3307.5

Compound interest (CI) = A-P = Rs 3307.5 – 3000 = Rs 307.5

(ii) Given, P = Rs 3000, rate = 18%, time = 2years

A = P (1 + R/100) n

= 3000 (1 + 18/100)2

= 3000 (118/100)2

= Rs 4177.2

Compound interest (CI) = A-P = Rs 4177.2 – 3000 = Rs 1177.2

(iii) Given, P = Rs 5000, rate = 10%, time = 2years

A = P (1 + R/100) n

= 5000 (1 + 10/100)2

= 5000 (110/100)2

= Rs 6050

Compound interest (CI) = A-P = Rs 6050 – 5000 = Rs 1050

(iv) Given, P = Rs 2000, rate = 4%, time = 3years

A = P (1 + R/100) n

= 2000 (1 + 4/100)3

= 2000 (104/100)3

= Rs 2249.72

Compound interest (CI) = A-P = Rs 2249.72 – 2000 = Rs 249.72

(v) Given, P = Rs 12800, rate = 7 ½ % = 15/2% = 7.5%, time = 3years

A = P (1 + R/100) n

= 12800 (1 + 7.5/100)3

= 12800 (107.5/100)3

= Rs 15901.4

Compound interest (CI) = A-P = Rs 15901.4 – 12800 = Rs 3101.4

(vi) Given, P = Rs 10000, rate = 20 % = 20/2 = 10% (quarterly), time = 2years = 2 × 2 = 4years

A = P (1 + R/100) n

= 10000 (1 + 10/100)4

= 10000 (110/100)4

= Rs 14641

Compound interest (CI) = A-P = Rs 14641 – 10000 = Rs 4641

(vii) Given, P = Rs 160000, rate = 10% = 10/2% = 5% (half yearly), time = 2years = 2×2 = 4 quarters

A = P (1 + R/100) n

= 160000 (1 + 5/100)4

= 160000 (105/100)4

= Rs 194481

Compound interest (CI) = A-P = Rs 194481 – 160000 = Rs 34481

......

Answered by rai64603
1

Answer:

Narasararaja Wodeyar I and Chikka Devaraja Wodeyar are the two kings Mysore kingdom flourished first at 17th cencutry. During early 20th century British came in power they resotred the dynasty to wodeyars by subsidary alliance from Nizams of Hyderabad.

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