3 number whose average is 112,the first number is 1/6th the sum of other 2.what is the first number?
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average of 3 numbers is112
sum of numbers =3×112=336
let the numbers be x, y, z
x+y+z=336
(y+z) /6=x
instead of x we can write (y+z)/6
(y+z) /6+y+z=336
multiple each term by6
y+z+6y+6z=336
7y+7z=336
divide by 7
y+z=48
x=(y+z) /6
=48/6
=8
sum of numbers =3×112=336
let the numbers be x, y, z
x+y+z=336
(y+z) /6=x
instead of x we can write (y+z)/6
(y+z) /6+y+z=336
multiple each term by6
y+z+6y+6z=336
7y+7z=336
divide by 7
y+z=48
x=(y+z) /6
=48/6
=8
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