Question

3 numbers are in ap if their sum is 15 and product is 45 find them

Answer 1

Let the numbers be ( a - d), a, (a +d)

According to first condition,

a - d + a + a + d = 15

=> 3a = 15

=> a = 5

Now,

(a - d) (a) (a +d) = 45

=> ( a^2 - d^2) (a) = 45

=> ( 25 - d^2) (5) = 45

=> 25 - d^2 = 9

=> d^2 = 16

=> d = 4

First number = ( 5- 4) = 1

Second number = 5

Third number = (5 + 4) = 9

Answer 2

Hey...☺

3 no.are

a-d , a , a+d

According to question

a-3d + a + a+3d = 15
3a = 15
a = 5


(a-d)(a)(a+d) = 45

(5-d) (5) (5+d) =45

{25 -d^2} 5 = 45

25 - d^2 = 9

d^2 = 16
.d =4

Then three numbers are --

a-d = 5-4 =1

a = 5

a+d = 5+4 = 9

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