Question

3 numbers are in ap whose sum is 6 and their product is -64.find the numbers​

Answer 1

Answer:

-4,2,8

Step-by-step explanation:

Let the three numbers be

a-d,a,a+d

Sum of numbers=6

a-d+a+a+d=6

a+a+a=6

3a=6

a=2

Product of numbers=-64

(a-d)×a×(a+d)=-64

(a-d)(a+d)×a=-64                      [(a-b)(a+b)=a²-b²]

(a²-d²)×a=-64

(2²-d²)2 = -64

4-d² = -32

-d² = -32-4

d² = 36

d = 6

therefore A.P. is (2-6),2,(2+6) = -4,2,8

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Answer 2

Answer:

let us consider 3 number are in AP is x-d, X, x+d