Question

(3) 'O'is the centre of the circle seg Op seg CD.
If OD = 20 cm., OP= 12 cm. then CD = ?
ato find​

Answer 1

Answer:

StepGiven- AB and CD are two chords of a circle with centre O.

OM⊥AB and ON⊥CD

AM=AN=4.5 cm

OM=ON=2 cm

Solution-

AM=AN=4.5 cm

∴AB=AM+AN=(4.5+4.5) cm =9 cm

OM and ON are the perpendicular distances of AB and CD respectively.

Since OM⊥AB and ON⊥CD

Now OM=ON=2 cm

∴AB and CD are equidistant from O.

∴AB=CD

Since chords of a circle, which are equidistant from the centre of the same circle are equal in length

Answer 2

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