Math, asked by rkirtika119, 2 months ago

prove that a constant function is a differntaiable function​

Answers

Answered by snehaagn47812
2

Answer:

f/(x) < 0 on a<x<b, then f is decreasing on a ≤ x ≤ b. If f/(x) ≤ 0 on a<x<b, then f is nonincreasing on a ≤ x ≤ b. The Increasing Function Theorem has a cousin: The Constant Function Theorem Suppose that f is continuous on a ≤ x ≤ b and differentiable on a<x<b. If f/(x)=0ona <x<b, then f is constant on a ≤ x ≤ b.

Answered by khushaliparakh8
0

Answer:

hold a pen in your hand

Step-by-step explanation:

and try to think about the question and try to solve something about it. keep faith on you ,u can do it

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