Question

3*. O PQRS is an isosceles trapezium
l(PQ) = 7 cm. seg PM I seg SR,
l(SM) = 3 cm,
Distance between two parallel
sides is 4 cm, find the area of
PQRS​

Answer 1

Answer:

Length of PQ = 7 cm

Length of PM = distance between two parallel sides = 4 cm

Length of SM = 3cm

see figure, length of SR = SM + MN + NR

because PQRS is isosceles trapezium, so, SR = NR = 3cm and MN = PQ = 7cm

so, Length of SR = 3cm + 7cm + 3cm = 13cm

now, area of PQRS = 1/2 { length of PQ + length of SR } × length of PM

= 1/2 { 7cm + 13cm} × 4cm

= 20cm × 2 cm

= 40 cm ²

Step-by-step explanation:

Answer 2

Answer:

Length of PQ = 7 cm

Length of PM = distance between two parallel sides = 4 cm

Length of SM = 3cm

see figure, length of SR = SM + MN + NR

because PQRS is isosceles trapezium, so, SR = NR = 3cm and MN = PQ = 7cm

so, Length of SR = 3cm + 7cm + 3cm = 13cm

now, area of PQRS = 1/2 { length of PQ + length of SR } × length of PM

= 1/2 { 7cm + 13cm} × 4cm

= 20cm × 2 cm

= 40 cm ²