Question

3) Obtain a quadratic equation whose roots are 3 and -10.​

Answer 1

$\huge{\mathcal{\green{\underline{Answer}}}}$

Let the roots of the quadratic equation be x

Hence ,

$x = 3 \\ x - 3 = 0 ............(1)$

$x = - 10 \\ x + 10 = 0.........(2)$

Multiplying (1) and (2) we get

$(x - 3)(x + 10) = 0 \\ x {}^{2} + 10x - 3x - 30 = 0 \\ {x}^{2} + 7x - 30 = 0$

Answer 2

sum of zeroes = -7

ie.-b/a therefore we get b=7 and a=1

product of zeroes = -30

ie.c/a therefore we get c= -30

from this we get equation as

x²+7x-30=0