Math, asked by cark, 1 year ago


3) On Sunday, Kanab, Amab and Pranay the threo volunteers of school's nature club went
around a circular mall road with 3 banners in hands 'Say No To Plastics' They knowingly
planned 16 minutes for Kanab. 24 minutes for Amab and 30 minutes for Pranav to walk around
the circular mail continuously Suppose each of them started activity from the same point in same
direction at 10:00a.m. At what time will all of them mest again at starting point?
plz answer my questions
I wil mark it as brainliest​

Answers

Answered by parmod66
4

Answer:

the correct answer is 2:00p.m


cark: plz explain it to me
cark: plz
parmod66: time ka LCM lene per vo sabhi starting point pe meet keraga
Answered by amitnrw
1

Given :  planned 16 minutes for Kanab. 24 minutes for Amab and 30 minutes for Pranav to walk around  the circular mall continuously .

Started at 10 AM

To find : At what time will all of them meet again at starting point

Solution:

Kanab  - 16 minutes

Amab  = 24 minutes

Pranav  - 30 minutes

Find LCM of all the times to get , the the time they will meet again

16 = 2 * 2  * 2 * 2

24 = 2 * 2 * 2 * 3

30 = 2 *  3 *  5

LCM = 2 * 2 * 2 * 2 * 3 * 5

= 240  minutes

= 4 hrs

They started at 10 AM so they will meet at  2 PM

They are doing social work to save environment  

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