Question

3. Perimeter of a rectangle is 34cm. If its breadth is of 5 cm, find the length
find
each diagonal of it​

Answer 1

Answer:

2(l+b)=34cm

l+5=17

l=12 cm

l²+b²=d² (diagonal =d)

12²+5²=d²

144+25=d²

169=d²

√169=d

d=13 cm

Answer 2

Given:

Perimeter of the rectangle = 34 cm

Breadth of the rectangle = 5 cm

To Find:

The length of the rectangle and the measurement of the diagonals.

Formula:

Perimeter of a rectangle = 2 ( Length + Breadth )

Pythagoras Theorem = AB^2 + BC^2 = AC^2

Solution:

Perimeter = 2 ( L + B ) = 34

Perimeter = 2 ( L + 5 ) = 34

Perimeter = L + 5 = 34/2 = 17

Perimeter = L = 17 - 5 = 12

Diagonals of a rectangle are equal.

By using Pythagoras Theorem, we get

Length^2 + Breadth^2 = Diagonal^2

or, 12^2 + 5^2 = Diagonal^2

or, 144 + 25 = Diagonal^2

or, √169 = Diagonal

or, 13 cm = Diagonal

Answer:

The length of the rectangle is 12 cm.

The measurement of the diagonals is 13 cm respectively.