Question

3 points
A chord 6 cm long is drawn in a circle with a diameter is equal to 10cm . Find its perpendicular distance from the centre.

Answer 1

Step-by-step explanation:

The distance of the chord from the centre will be 8cm.

Draw a circle. Make a chord say AB (12cm given). Label the centre of the circle as O. Join OA and OB. OA and OB are the radii of the circle.

Diamete is 20 cm therefore radius will be 10 cm.

Hence, OA = OB = 10cm.

Draw a perpendicular OD on AB. This OD is the distance of the chord from the centre which we are required to find.

By the property of circles, we know this perpendicular OD will bisect the chord AB. Therefore, AD = DB = 6 cm.

Now, triangle ODB is a right triangle right angled at D where DB = 6cm and OB = 10cm.

Apply pythagorus theorem,

OB^2 = DB^2 + OD^2

(10)^2 = (6)^2 + OD^2

OD^2 = 64

Hence OD = 8cm

Answer 2

OD = 8cm

please mark my answer brainliest ⭐