If A, B, C, D are angles of a cyclic quadrilateral, prove that
(i) cot A + cot B + cot C + cot D = 0
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Step-by-step explanation:
In a cyclic quadrilateral sum of all angles is equal to 360degrees so let us consider A+C = 180degrees and B+D = 180degrees so now add cotton on both sides then cotA+cotB = cot180 (cot 180=0) then cotA+cotB=0 and same B+D so cot A+cotB+cotC+cotD=0
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If A, B, C, D are angles of a cyclic quadrilateral, prove that
(i) cot A + cot B + cot C + cot D = 0
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