Question

3. Prove that (1 - sin 0 + cos 0)^2 = 2 (1 + cos 0) (1 - sin 0).​

Answer 1

Answer:

we know that sin 0=0

cos0=1

LHS : (1-sin0+cos0)^2

=(1-0+1)^2

=4

RHS: 2(1+COS0) (1-sin0)

=2(1+1)(1-0)

=4

lhs=rhs

hence proved

Step-by-step explanation:

Answer 2

we know that sin 0=0

cos0=1

LHS : (1-sin0+cos0)²

=(1-0+1)²

=4

RHS: 2(1+COS0) (1-sin0)

=2(1+1)(1-0)

=4

lhs=rhs

hence proved

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