Question

3. Rajpal deposited 5000 with a finance company for 5 years at 12% per annum. What is the
compound interest that Rajpal gets after 5 years?

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Answer 1

Interest in compound interest = P (1 + \frac{r}{100})^{n}(1+

100r ) n

Here,

P = principal amount = 5000 rupees

r = rate of interest = 12%

n = number of years = 5 yrs

Substituting the values in the formula, we get,

Interest = 5000(1 + \frac{12}{100})^{5}5000(1+ 10012 ) 5

⇒ Interest = 5000 (\frac{112}{100} \times \frac{112}{100} \times \frac{112}{100} \times \frac{112}{100} \times \frac{112}{100})5000(100112×100112 × 100112

× 100112

⇒ Interest = 5000 × 1.76234

⇒ Interest = 8811.7 rupees

Hope it Helps u!!

Answer 2

Answer:

3811.708416 Rs

Step-by-step explanation:

Given : principal = 5000Rs

Time (n) = 5 years

Rate (R) = 12 %

C.I. = ?

Amount ( A ) = ?

A = P ( 1 + R/100)^n

A = 5000 ( 1 + 12/100) ^5

= 5000 ( 112/100 ) ^5

= 5000 × (1.12)^5

= 5000 ×1.7623416832

= 8811.708416

Therefore , Amount= 8811.708416 Rs

C.I. = A - P

= (8811.708416 - 5000) Rs

= 3811.708416 Rs

Hope you will understand....and it will help you ......Thank you.....