3 rase to the power n minus 3 raise to the power n-2 is equal to 648 . Find n raise to the power 3
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Question:
3^n - 3^(n - 2) = 648
Find n^3.
Solution:
3^n - 3^(n - 2) = 648
=> 3^(n - 2 + 2) - 3^(n - 2) = 648
=> 3^(n - 2) · 3^2 - 3^(n - 2) = 648
=> 3^(n - 2) (3^2 - 1) = 648
=> 3^(n - 2) (9 - 1) = 648
=> 3^(n - 2) · 8 = 648
=> 3^(n - 2) = 648 / 8
=> 3^(n - 2) = 81
Now,
log_3 (81) = n - 2
=> log_3 (3^4) = n - 2
=> 4 log_3 (3) = n - 2
=> 4 · 1 = n - 2 [Because log_a (a) = 1]
=> 4 = n - 2
=> n = 4 + 2
=> n = 6
So,
n^3 = 6^3 = 216
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