Question

3 rd question plss answer this question

Answer 1

HELLO......FRIEND!!

THE ANSWER IS HERE,

Given that , PQ||BC

In triangleAPQ & ABC,

angleAQP=angleACB

angleAPQ=angleABC

So,By AA similarity.

TriangleAPQ~TriangleABC

Ar of triangleAPQ/Ar of triangleABC=(AP/AB)^2

=> (AP/(AP+PB))^2

=> (1/(1+2))^2

=> (1/3)^2

=> 1/9.

:-)Hope it helps u.

Answer 2

Hi Friend !!!!

==================

Given That ,

PQ || BC

in triangle APQ and in triangle ABC,

angle APQ = angle ABC

angle AQP = angle ACB

So , by AA Similarity they are similar

Δ APQ ~ Δ ABC

area of Δ ABC / area of Δ APQ = (AP / AB )²

= (AP /(AP+PB ))²

= (1/1+2)²

= 1/3²

= 1/9

Hope it helps u