3 resistors 4 ohm,6 ohm and 12 ohm are connected in parallel.The combination of the above resistors is connected in series to a resistance of 2 ohm and then to a battery of 6 volt. draw a circuit diagram and calculate:
a)current in the main circuit.
b)current flowing through each of the resistors in parallel.
c)potential difference across the 2 ohm resistor.
(diagram is not necessary
Answers
Answered by
8
b) equivalent resistance in parallel = 1.2 ohm
(already found in picture )
v = ir
I = v/r
I = 6/ 1.2
I = 5 Amp.
c) current flowing through 2 ohm = 6/3.2
v= ir
v = (6/3.2)2
v =3.74 v
(already found in picture )
v = ir
I = v/r
I = 6/ 1.2
I = 5 Amp.
c) current flowing through 2 ohm = 6/3.2
v= ir
v = (6/3.2)2
v =3.74 v
Attachments:
Gourav2002:
I hope this will be helpful . please make it brainliest if it really helps you. thank you
Answered by
2
Answer:
I hope you may find this helpful.
Attachments:
Similar questions