Question

3 resistors are connected as shown in the diagram through the resistor 5 ohm a current of one ampere is flowing . What is the current in other two circuit?

Answer 1

The answer is total resistance = 1/10 + 1/15 + 5 = 11 ohm
I = 1A
V =IR
V= 1 * 5 = 5V (ACCROSS AB)
V = 1 * 11 = 11V (ACCROSS AC)
V (ACCROSS BC i.e OTHER 2 RESISTORS) = 11 - 5 =6V (AC-AB=BC)

I = V/R
I1 = 6/10 = 0.6
I2= 6 / 15 = 0.4 A

i hope it will help you

Answer 2

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➧ Total resistance
➾ 1 / 10 + 1 / 15 + 5
➾ 11 ohm

I = 1A 　　　,　　 V = IR

V ➾ 1 × 5
　➾ 5V (ACCROSS AB)

V = 1 × 11
　➾11V (ACCROSS AC)

➧ V (ACCROSS BC i.e OTHER 2 RESISTORS)

➾ 11 - 5
➾ 6V (AC - AB = BC)

➧ I = V / R

I1 = 6 / 10
➾ 0.6 ...✔

I2 = 6 / 15
➾ 0.4 A ...✔

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Thanks...✊