Question

3 resistors of 2ohm , 3 ohm and 6 ohm are given. What is the highest resistance that you can get using all of them?

Answer 1

Answer: 11ohm

Explanation: R(Highest) = R1 + R2 + R3

using Series Connection you get the highest resistance and R(lowest) = 1/R1 + 1/R2 + 1/R3 Using Parallel connection you can get the lowest Resistance

Answer 2

"$\bf{ \pmb{ \underline{\gray{GIVEN}}}} \\ \sf \: \small{ Three \: resistors \: of \: 2 Ω, 3 Ω \: and \: 6 Ω \: are \: given \: respectively. }\\ \\ \\ \bf{ \pmb{ \underline{\gray{TO \: FIND }}}}\\ \rm \small{Least \: value \: of \: the \: three \: resistances. }\\ \\ \\ \bf { \pmb{ \underline{\gray{ SOLUTION}}}} \\ \tt \tiny{For \: the \: max \: value \: of \: the \: resistances, resistor \: are \: connected \: in \: \bf{\blue{Series \: Combination}} }\\ \tt \tiny{For \: the \: least \ value\ of \: the \: resistances, resistor \: are \: connected \: in\ \bf{\green{Parallel \: Combination}} } \\ \\ \cal \: \small{\red{Connect \: the \: resistor \: in \: series \: for \: getting \: highest \: value :} }\\ \\ \begin{gathered}\small \rm R_{eq} = {R_1} + {R_2} + {R_3} \\ \\ \small \rm R_{eq} = 2 + 3 + 6 \\ \\ \large { \boxed{\bf \blue{R_{eq} = 11 Ω}}}\end{gathered}$