Physics, asked by nethraezhil, 1 year ago

3 resistors of resistance R1,R2,R3 are connected in i)parallel ii)series. write expression for equivalent resistance of combination in each case

Answers

Answered by Anonymous
230

In series:

Since, in series combination the values of resistances are added, the value of equivalent resistance is larger than the largest value of resistance in the combination of resistors.

R_{eq} = R_{1} + R_{2} + R_{3}

In parallel:

In parallel connection, the value of equivalent resistance is smaller than the smallest value of resistance in the combination of resistors.

The expression for equivalent resistance in parallel combination will be,

\frac{1}{R_{eq}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}\\\\R_{eq} = \frac{R_{1}R_{2}R_{3}}{R_{1}R_{2}+R_{2}R_{3} + R_{1}R_{3}}

Answered by arfayein42
24

Hello Guys!!!!

In Series

Req=R1+R2+R3

In Parallel

Req=1/R1+1/R2+1/R3

Thanks

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