Question

3 root 192 - 2/3 root 1/3 + root 1/3

Answer 1

Hope this helps u dude

Answer 2

Answer:

$\frac{217\sqrt{3}}{9}$

Step-by-step explanation:

$3\sqrt{192}-\frac{2}{3}\sqrt{\frac{1}{3}}+\sqrt{\frac{1}{3}}$

$=3\sqrt{64\times 3}-\frac{2}{3}\times \frac{1}{\sqrt{3}}+\frac{1}{\sqrt{3}}$

$=24\sqrt{3}-\frac{2}{3\sqrt{3}}+\frac{1}{\sqrt{3}}$

$=\frac{24\sqrt{3}\times 3\sqrt{3}-2+3}{3\sqrt{3}}$

$=\frac{24\times 9+1}{3\sqrt{3}}$

$=\frac{216+1}{3\sqrt{3}}$

$=\frac{217}{3\sqrt{3}}$

By rationalizing,

$=\frac{217}{3\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}$

$=\frac{217\sqrt{3}}{9}$