Question

3 root 2 +1 ÷2root2-3​

Answer 1

Answer:

$\frac{3\sqrt{2}+1}{2\sqrt{2}-3}= -(21+15\sqrt{2})$

Step-by-step explanation:

$\frac{3\sqrt{2}+1}{2\sqrt{2}-3}$

$=\frac{(3\sqrt{2}+3)(2\sqrt{2}+3)}{(2\sqrt{2}-3)(2\sqrt{2}+3)}$

$=\frac{12+9\sqrt{2}+6\sqrt{2}+9}{(2\sqrt{2})^{2}-3^{2}}\\=\frac{21+15\sqrt{2}}{8-9}\\=-(21+15\sqrt{2})$

Therefore,

$\frac{3\sqrt{2}+1}{2\sqrt{2}-3}= -(21+15\sqrt{2})$

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