Math, asked by connect2saazeez, 7 months ago

3 + root 2 by 4 root 2

Answers

Answered by Anonymous
1

Answer:

 =  \frac{3 +  \sqrt{2} }{4 \sqrt{2} } \\  \\  =

Answered by Delta13
2

We have

 \frac{3 +  \sqrt{2} }{4 \sqrt{2} }  \\

So we have to rationalize the denominator.

  \implies\frac{3 +   \sqrt{2}  \times (4 \sqrt{2} )}{4 \sqrt{2} \times (4 \sqrt{2} ) }   \\  \\   \implies \:  \frac{3(4 \sqrt{2}  )+ \sqrt{2}  (4 \sqrt{2}) }{(4 \sqrt{2})  {}^{2} }  \\  \\  \implies \:  \frac{12 \sqrt{2}  + 4(2)}{(16(2))} \\  \\  \implies \:  \frac{12 \sqrt{2} + 8 }{32}  \\  \\  \implies \:  \frac{4(3 \sqrt{2} + 2) }{32}  \\  \\  \green{\implies \:  \frac{3 \sqrt{2}  + 2}{8} }

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