Question

3 root 2 /root 6+root 3  + 2 root 3 /root 6 +2  - 4 root 3/root 6 - root 2

Answer 1

$3 \frac{\sqrt{2} }{\sqrt{6}} + \sqrt{3} + 2 \frac{\sqrt{3}}{\sqrt{6}} -4 \frac{\sqrt{3}}{\sqrt{6}} - \sqrt{2} \\ \\ 3 \frac{\sqrt{2} }{\sqrt{3*2}} + \sqrt{3} + 2 \frac{\sqrt{3}}{\sqrt{3*2}} -4 \frac{\sqrt{3}}{\sqrt{3*2}} - \sqrt{2} \\ \\ \frac{3\sqrt{2}+\sqrt{3}*\sqrt{3*2} +2 \sqrt{3} - 4 \sqrt{3} - \sqrt{2}*\sqrt{3*2} } {\sqrt{2*3}} \\ \\ \frac{3\sqrt{2}+3\sqrt{2}+2\sqrt{3}-4\sqrt{3}-2*\sqrt{3}}{\sqrt{3*2}} \\ \\ \frac{6\sqrt{2}-4\sqrt{3}}{\sqrt{3*2}}$

$\frac{2*\sqrt{3}*\sqrt{3}*\sqrt{2}- 2 \sqrt{2}*\sqrt{2}*\sqrt{3} }{\sqrt{3*2}} \\ \\ 2\sqrt{3} - 2\sqrt{2}$