Question

3 root 3 + 2 root 27 +7/root 3

Answer 1

3√3+2√27/√3

= 3√3 + 6√3 + ( 7√3 )/3

= 9√3 + ( 7√3 )/3

= [ 27√3 + 7√3 ]/3

= ( 34√3 )/3

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Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

$\sf{ =3 \sqrt{3} + 2 \sqrt{27} + \frac{7}{ \sqrt{3} } }$

$\sf{ =3 \sqrt{3} + 2 \times 3 \sqrt{3} + \frac{7}{ \sqrt{3} } }$

$\sf{ = 3\sqrt{3} + 6 \sqrt{3} + \frac{7 \sqrt{3} }{3} }$

$\sf{ = \sqrt{3} \bigg(3 + 6 + \frac{7}{3} \bigg) }$

$\sf{ = \sqrt{3} \bigg(9 + \frac{7}{3} \bigg) }$

$\sf{ = \sqrt{3} \times \frac{34}{3} }$

$= \boxed{ \sf{ \frac{34}{3} \sqrt{3} } }\: \: \: \bf{ Ans.}$