3 + root 7/3-root 7 is equal to a+broot7
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Answered by
1
Hi ,
LHS = ( 3 + √7 )/( 3 - √7 )
Rationalize the denominator,
= [(3+√7)(3+√7)]/[(3-√7)(3+√7)]
= ( 3 + √7 )² / [ 3² - ( √7 )² ]
= [ 3² + ( √7 )² + 2 × 3 × √7 ]/( 9 - 7 )
= ( 9 + 7 + 6√7 )/2
= ( 16 + 6√7 )/2
= 16/2 + ( 6√7 )/2
= 8 + 3√7 -----( 1 )
= a + b√7 ----( 2 ) [ given RHS ]
Compare ( 1 ) and ( 2 ) , we conclude
that ,
a = 8 , b = 3
I hope this helps you.
: )
LHS = ( 3 + √7 )/( 3 - √7 )
Rationalize the denominator,
= [(3+√7)(3+√7)]/[(3-√7)(3+√7)]
= ( 3 + √7 )² / [ 3² - ( √7 )² ]
= [ 3² + ( √7 )² + 2 × 3 × √7 ]/( 9 - 7 )
= ( 9 + 7 + 6√7 )/2
= ( 16 + 6√7 )/2
= 16/2 + ( 6√7 )/2
= 8 + 3√7 -----( 1 )
= a + b√7 ----( 2 ) [ given RHS ]
Compare ( 1 ) and ( 2 ) , we conclude
that ,
a = 8 , b = 3
I hope this helps you.
: )
Answered by
0
Hi,
Please see the attached file!
Thanks
Please see the attached file!
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