3 + root 7 divided by 3 minus root 7 rationalize the denominator
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0
Answer:
THE ANSWER IS HERE,
= > \: \frac{3 + \sqrt{7} }{3 - \sqrt{7} }=>
3−
7
3+
7
= > \: \frac{3 + \sqrt{7} }{3 - \sqrt{7} } \times \frac{3 + \sqrt{7} }{3 + \sqrt{7} }=>
3−
7
3+
7
×
3+
7
3+
7
= > \: \: \frac{( {3 + \sqrt{7} )}^{2} }{ {3}^{2} - { \sqrt{7} }^{2} }=>
3
2
−
7
2
(3+
7
)
2
= > \: \frac{9 + 7 + 6 \sqrt{7} }{2}=>
2
9+7+6
7
= > \: \frac{16 + 6 \sqrt{7} }{2}=>
2
16+6
7
= > \: 8 + 3 \sqrt{7} .=>8+3
7
.
From the question,
= > \: 8 + 3 \sqrt{7} = a + b \sqrt{7}=>8+3
7
=a+b
7
= > \: a = 8 \:=>a=8
= > \: b = 3.=>b=3.
Answered by
0
from the question
=(3+√7 )/3 -√7
= ( 9+√7 - 3√7 ) /3
= (9 -2√7 ) /3
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