3+root5 is a root of x² +px +q=0, then (p,q)=
d) (3,5)
a) (4,-6)
b) (-6,4)
c)(6,4)
Answers
Answered by
2
Step-by-step explanation:
(2+
3i
)
2
+p(2+
3i
)+q=0
4−3+4
3
i+2p+
3
pi+q=0
⇒(1+2p+q)+(4
3
+
3
p)i=0
⇒2p+q=−1; p=−4
⇒q=−1+8=7
⇒ (A).
solution
Answered by
7
Answer:
i dont learnt route sums please sorry
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