3+root7/3-root7 = a+b root7 find a and b
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Answered by
5
3 + √7/(3-√7) = a+b√7,
3 + √7/(3-√7) × (3+√7)/(3+√7) = a+b√7,
3 + √7(3+√7)/(3²-√7²) =a+b√7,
3 + (3√7+7)/(9-7) = a+b√7,
3 + (3√7+7)/2 = a+b√7,
(6+3√7+7)/2 = a+b√7,
(13+3√7)/2 = a+b√7,
13/2 + 3√7/2 = a+b√7,
then
a=13/2,
b=3/2
3 + √7/(3-√7) × (3+√7)/(3+√7) = a+b√7,
3 + √7(3+√7)/(3²-√7²) =a+b√7,
3 + (3√7+7)/(9-7) = a+b√7,
3 + (3√7+7)/2 = a+b√7,
(6+3√7+7)/2 = a+b√7,
(13+3√7)/2 = a+b√7,
13/2 + 3√7/2 = a+b√7,
then
a=13/2,
b=3/2
Answered by
4
Hey here is your answer ⤵⤵⤵
We have to rationalise The denominator
Multiply by 3+root 7
On rationalizing we get
⏩
Comparing both sides we get
a=8 and b=
hope it helps you
Please mark as BRAINLIEST. ✔✔
We have to rationalise The denominator
Multiply by 3+root 7
On rationalizing we get
⏩
Comparing both sides we get
a=8 and b=
hope it helps you
Please mark as BRAINLIEST. ✔✔
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