Math, asked by starlion698, 1 year ago

3+root7/3-root7 = a+b root7 find a and b

Answers

Answered by adee1729
5
3 + √7/(3-√7) = a+b√7,


3 + √7/(3-√7) × (3+√7)/(3+√7) = a+b√7,


3 + √7(3+√7)/(3²-√7²) =a+b√7,


3 + (3√7+7)/(9-7) = a+b√7,


3 + (3√7+7)/2 = a+b√7,


(6+3√7+7)/2 = a+b√7,

(13+3√7)/2 = a+b√7,

13/2 + 3√7/2 = a+b√7,


then

a=13/2,

b=3/2
Answered by Ramlayaksingh3
4
Hey here is your answer ⤵⤵⤵


 \frac{3 +  \sqrt{7} }{3 -  \sqrt{7} } = a + b

We have to rationalise The denominator

Multiply by 3+root 7

On rationalizing we get


8 + 3 \sqrt{7}  = a + b
Comparing both sides we get

a=8 and b=
3 \sqrt{7}

hope it helps you

Please mark as BRAINLIEST. ✔✔
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