3 से 7.5 ग्राम kclo3 रिलेटेड टू प्रोड्यूस केसिया जालौर टू फाइंड द अमाउंट ऑफ कीजिए rano2 प्रोड्यूस्ड
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At NTP, 11.2 L of oxygen corresponds to 22.411.2 =0.5mol2KClO 3 heat 2KCl+3O 2 Thus, 2 moles of potassium chlorate on heating gives 3 moles of oxygen.Thus, 32 ×0.5= 31 moles of potassium chlorate on heating gives 11.2 L of oxygen at NTP.Hence, the
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At NTP, 11.2 L of oxygen corresponds to 11.2/22.4 = 0.5 mol 2KClO3 heat 2KCl + 3O2 Thus, 2 moles of potassium chlorate on heating gives 3 moles of oxygen..
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