3. satellite is orbiting around the earth at a mean radius of
16 times that of the geostationary orbit. What is the period
of the satellite ?
32 days
16 days
64days
8 days
Answers
Answered by
0
Answer:
(T
1
2
/T
2
2
)=(R
1
3
/R
2
3
)
⇒T
2
2
=(
R
1
R
2
)T
1
2
⇒T
2
=(
R
1
R
2
)
3/2
T
1
For the geostationary satellite, T
1
=1 day(24 hrs.)
∴T
2
=(
R
9R
)
2
3
=27 days
So it will complete one revolution in 27 days
ω=2π/T
2
=
27×24×3600
2π
rad/s
2.693×10
−6
rad/sec.
Explanation:
Understand equation
I hope you get help from me
Answered by
0
Eight days................
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