Question

find the roots of qudratic equation x square - 3 x minus 10 by prime factorization method ​

Answer 1

Given quadratic equation : $x^{2}$- 3x - 10 = 0

$x^{2}$- 3x - 10 = 0

$x^{2}$ + 2x - 5x - 10 = 0

x ( x + 2 ) - 5 ( x + 2 ) = 0

(x+2)(x-5)=0

x+2=0                  x-5=0

x=-2                     x=5

The roots of the given quadratic equation are 5 , -2.

Hope it helps!!

Answer 2

Answer:

x^2-3x-10

=x^2-5x+2x-10

=x(x-5)+2(x-5)

=(x+2) (x-5)