Math, asked by chandayadav33197, 10 months ago

3. Select UNE correct answer
+4.0
A father is 7 times as old as his son. Two years ago, the father was 13 times as old as his son. Son's
present age is
एक पिता अपने पुत्र की आयु का 7 गुना है। दो साल पहले पिता अपने पुत्र की आयु से 13 गुना था। पुत्र की वर्तमान
आयु है।
(A) 5 years वर्ष
(B)4 years वर्ष
(C) 6 years ar
(D)8 years वर्ष​

Answers

Answered by revanthika18
0

Answer:

the answer is (B) 4 years

Answered by Anonymous
3

The correct answer is B.4 years.

GiveN:-

A father is 7 times as old as his son, two years ago the Father was 13 times as old as his son.

To FinD:-

The present age of son.

SolutioN:-

Let the present age of the son be x years.

Let the present age of the father be 7x years.

2 years ago their ages were:-

Son = (x - 2) years.

Father = (7x - 2) years.

It is said that two years ago the Father was 13 times as old as his son.

According to the question,

\large\implies{\sf{7x-2=13(x-2)}}

\large\implies{\sf{7x-2=13x-26}}

\large\implies{\sf{-2+26=13x-7x}}

\large\implies{\sf{24=6x}}

\large\implies{\sf{\dfrac{24}{6}=x}}

\large\implies{\sf{\dfrac{\cancel{24}}{\cancel{6}}=x}}

\large\implies{\sf{4=x}}

\large\therefore\boxed{\bf{x=4.}}

Their present ages:-

Son's age = x = 4 years.

Father's age = 7x = 7 × 4 = 28 years.

The present age of the son is 4 years.

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