Question

3.
Show that
(a)
cos 0 + sin(270° + 8) - sin(270° - 0) +
cos(180° + 0) = 0​

Answer 1

Answer:

Step-by-step explanation:

cos 0 + sin(270° + 8) - sin(270° - 0) + cos(180° + 0) = 0​

sin(270-0)=sin (180+(90-0))= -sin(90-0) = -Cos 0

cos(180+0)= -cos 0

sin(270 +8)= sin(180+(90+8))= -sin (90+8)= -cos 8

cos 0-cos 8 -(-cos 0)-cos 0=0

1-1+1-1=0

0=0