Question

3 sin 62/ cos 28 - sec 42/ cosec 48

Answer 1

3sin62/cos28 - sec42/cosec48

=3cos(90-62)/cos28 - cosec (90-42)/cosec48

=3cos28/cos28 - cosec48/cosec48

=3-1=2

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Answer 2

The value of the given expression is 2.

Step-by-step explanation:

The given expression : $\dfrac{3\sin 62^{\circ}}{\cos28^{\circ}}-\dfrac{\sec 42^{\circ}}{cosec 48^{\circ}}$

Since cos (90°-A) =sin A

cosec (90°-A) = sec A

Therefore , the above expression will become

$\dfrac{3\sin 62^{\circ}}{\cos(90^{\circ}-62^{\circ})}-\dfrac{\sec 42^{\circ}}{cosec (90^{\circ}-48^{\circ})}$

$=\dfrac{3\sin 62^{\circ}}{\sin 62^{\circ}}-\dfrac{\sec 42^{\circ}}{\sec 42^{\circ}}$

$=\dfrac{3}{1}-\dfrac{1}{1}=2$

Hence, the value of the given expression is 2.

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