Question

3 √sin0 = coso, Find the value of 3cos0²+ 2 cos0 /3cos0 + 2​

Answer 1

3 √sin0 = coso, Find the value of 3cos0²+ 2 cos0 /3cos0 + 2= cos0 /3cos0 + 2=

Answer 2

Answer:

Given:- sinθ+cosθ=

2

cosθ

To prove:- cosθ+sinθ=

2

sinθ

Proof:-

sinθ+cosθ=

2

cosθ

Squaring both sides, we get

sin

2

θ+cos

2

θ+2sinθcosθ=2cos

2

θ

⇒sin

2

θ−cos

2

θ+2sinθcosθ=0

Subtracting 2sin

2

θ both sides, we have

−sin

2

θ−cos

2

θ+2sinθcosθ=−2sin

2

θ

sin

2

θ+cos

2

θ−2sinθcosθ=2sin

2

θ

(cosθ−sinθ)

2

=2sin

2

θ

⇒cosθ−sinθ=

2

sinθ

Hence proved.