Question

3(sina-cosa)^4+6(sina+cosa)^2+4(sin^6a)=
a)13-4cos^2a+6sin^2a.cos^2a
b)13-4 cos^2a
c)13-4cos^2a+6cos^2a
d)13-4 cos^2a+2sin^a

Answer 1

Step-by-step explanation:

trigonometric ratios