Question

3) Solve the following equati
on by Cramer's method 3x - 4y = 10; 4x +3y=5


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Answer 1

Answer:

Step-by-step explanation:

a1=3,b1=-4,c1=10

a2=4,b2=3,c2=5

D=a1    b1 = 3  -4

    a2   b2   4   2

  =[3×2]-[4×(-4)]

  =6-[-16]

  =6+16

D=22

Dx=c1   b1 = 10  -4

      c2  b2    5    3

    =[10×3]-[5×(-4)]

    =30-[-20]

Dx=30+20

Dx=50

Dy=a1   c1 = 3   10

     a2  c2   4   5

   =[3×5]-[4×10]

   =15-40

Dy=-25

x=Dx/D

=50/22

x=25/11

y=Dy/D

y=-25/22