Question

3. Solve the following equations
1) 5x - 8 = 2x - 2
2) 3x - 2 =7
4) x+4/x -4 =3/2
5) 5x - 3/1-2x=-12/5​

Answer 1

Step-by-step explanation:

this is the answer of the question

Answer 2

Answer:

Step-by-step explanation:

1) 5x - 8 = 2x - 2

=> Transposing 2x to LHS  and -8 to LHS

5x-2x = -2+8

=> 3x = 6                                                                         [as 5x-2x=3x and -2+8=6]

=> Transposing 3 to RHS

x = $\frac{6}{3}$

x=3

2) 3x - 2 =7

=> Transposing -2 to RHS

3x = 7+2

=> 3x = 9

=> Transposing 3 to RHS

x = $\frac{9}{3}$

=>x = 3

3) x+4/x -4 =3/2

=>Expressing the equation as

$\frac{x+4}{x-4}$ = $\frac{3}{2}$

=> By cross multiplication

3[x-4] = 2[x+4]

=> 3x-12 = 2x+8

=> Transposing 2x to LHS and -12 to RHS

3x-2x = 8+12

=> x= 20

4) 5x - 3/1-2x=-12/5​

=>Expressing the equation as

$\frac{5x-3}{1-2x}$ = $\frac{-12}{5}$

=>By cross multiplication

-12[ 5x-3] = 5[1-2x]

=>-60x+ 36 = 5-10x

=> -60-5 = -10x- 36x

=>-65 = -46x

=> x = $\frac{-65}{-46}$

HOPE IT HELPS YOU

PLS MARK BRAINLIEST