Question

3 spheres of radius 3cm, 4cm and 5cm are melted and recast to a single sphere. Find the Radius of sphere​

Answer 1

Answer:

6 cm

Step-by-step explanation:

The total volume of the three spheres is:

  (4/3)π(3)3 + (4/3)π(4)3 + (4/3)π(5)3

= (4/3)π(33+43+53)

= (4/3)π(216)

= (4/3)π(6)3

The "new" sphere would have radius = 6 cm

Answer 2

Answer:

R=6 Cm

Step-by-step explanation:

$r1 = 3cm \\ r2 = 4cm \\ r3 = 5cm \\ new \: sphere \: = sum \: of \: 3 \: spheres \\ \frac{4}{3} \pi \: {r}^{3} = \frac{4}{3} \pi \: {(r1)}^{3} + \frac{4}{3} \pi \: {(r2)}^{3} + \frac{4}{3} \pi {(r3)}^{3} \\ \frac{4}{3} \pi \: {r}^{3} = \frac{4}{3} \pi \: ( {(r1)}^{3} + ( {r2)}^{2} + {(r3)}^{3} \\ {r}^{3} = 27 + 64 + 125 \\ {r}^{3} = 216 \\ r = 6cm$