Question

3)Starting from rest,a car travels with a uniform acceleration of 5m/s^2.

a) Calculate it's velocity after 20s.

b) In this time,how much w
ill be it's displacement?​

Answer 1

Explanation:

v=u+at

u=0

=0+5m/s

2

×60s

a=5m/s

2

=0+300m/s

t=1 min

So, t=60sec

=300m/s

s=ut+1/2at

2

=0×60+1/2×5×60

2

=9000m

Answer 2

Initial velocity u = 0 m/s

Acceleratio, a = 5m/s^2

Using first equation of motion.
v = u + at
V = 0 + 5x20
V = 100m/s

For displacemnet use 3rd equation of motion.
Let displacement be s.

V^2 - U^2 = 2as

(100)^2 - 0 = 2(5)(s)
10000 = 10s
S = 10000/10
S = 1000m (Answer)