3. Subtract:
(a)6a2 from 10a
(b) –3x2 from 5x2
(C) x2 from 3x + 5
(d) 2a + b from 6a + 4b
(e) – x2 + 10x - 5 from 5x2 + 6x - 7
(f) alb – 5) from b(5 – a)
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Answer:
a) 6a² from 10a
=> 10a -6a²
b) -3x² from 5x²
5x² - (-3x²)
5x²+3x²
=>8x²
c) x² from 3x+5
=>3x+5 - x²
d) 2a+b from 6a+4b
6a+4b - (2a+b)
6a+4b-2a-b
6a-2a+4b-b
=>4a+3b
e) -x²+10x-5 from 5x²+6x-7
5x²+6x-7 - (-x²+10x-5)
5x²+6x-7+x²-10x+5
5x²+x²+6x-10x-7+5
=>6x²-4x-2
f) a(b-5)from b(5-a)
b(5-a) - [a(b-5)]
5b-ab - [ab-5a]
=>5b-ab -ab+5a
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