3. Take any point in the interior of a triangle ABC as shown in the figure.
IS
(a) AO + BO > AB
(c) AO + OC > AC
(b) OB + OC > BC
(d) AB + BC > AC?
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In an isosceles triangle ABC, with AB = AC, the bisectors of ∠B and ∠C intersect each other at O. Join A to O. Show that:
(i) OB = OC (ii) AO bisects ∠A
Ans. (i) In ΔABC, we have
∴ AB = AC
[Given]
∠C = ∠B
[Angle opposite to equal sides are equal]
or ∠OCB = ∠OBC
⇒ OB = OC
[Sides opposite to equal angles are equal]
(ii) In ΔABO and ΔACO, we have
AB = AC
[Given]
OB = OC
[Proved]
∴ Using SAS criteria,
ΔABO ≌ ΔACO
⇒ ∠OAB = ∠OAC
[c.p.c.t.]
⇒ AO bisects ∠A.
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