Question

√3 tanA=3 sinA then sin²A-cos²A

Answer 1

1/3 Is the required answer

Answer 2

Given: √3 tanA=3 
⇒ tanA =3/√3 ( rationalise this fraction )
⇒ tanA = √3
⇒ tanA = tan60°
⇒  A = 60°
∴sin²A-cos²A
⇒sin60°²-cos60°²⇒1/2