3.The 17 ^ (th) term of an A.P. exceeds its 10 ^ (th) term by 7.Find the common
difference..
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Answer: common difference d = 1
Step-by-step explanation:
17th term will be,
t17 = a + 16d --- by tn = a + (n-1)d
10th term will be,
t10 = a + 9d --- by tn = a + (n-1)d
The 17th term of an A.P exceeds its 10th term by 7.
acc. to given condition,
t17 = t10 + 7
a + 16d = a + 9d +7 (putting in the values that we got above)
a - a + 16d - 9d = 7
7d = 7
d = 7/7
d = 1
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