Question

3. The approximate wavelength of a photon
of energy 2.48 eV is​

Answer 1

Answer:

2.48 eV=5000AO

Explanation:

We know that,

E(eV)=λA012375

⇒λ=(2.48)12375

λ=4989.9A0≈5000A0

Approximate wavelength of a photon of energy 2.48eV=5000A0.